... 13,080s.” -- 7,600s." - 1,248s” + 64s") so f(0) = 1, and (6.18) becomes (6.20) > (...) f(s) = 0 (mod 2048). Since the denominator in (6.19) is odd, the numerator of each term will contain all powers of two for the quotient. From (6.19) ...
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