4 choose 2 =
6
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How do you solve 4 choose 2?
What is the value of 4C2?
1
Answer: Combination expressions can be solved using the following formula:
2
nCr = n!/[r! (n – r)!
3
Substituting four and two into the formula, n = 4 and r = 2, the result is,
4
4C2 = 4!/ [2! (4 – 2)!
5
= 4!/ (2! 2!)
6
= (4×3×2×1)/ (2×1×2×1)
7
= 6.
8
Hence, the value of 4C2 is 6.
How many combinations of 2 out of 4?
Therefore there are 6 combinations of 4 objects taken two at a time.
What is the value of 4 combination 2?
Now we have obtained the expression (2). In this expression we have to divide 24 by 4. If we divide 24 by 4 then we get 6. Hence we have obtained the value of the combination that is 6 or ${}^{4}{{C}_{2}}=6$.
What does 5 choose 2 mean?
We want to know how to find 5 choose 2. This problem is often written using the notation 5 C 2 , and it means we're looking for how many ways there are to choose 2 objects from 5 objects when the order of the objects doesn't matter. This is called a combination of 2 objects chosen from 5 objects.
Looking at the formula, we must calculate “6 choose 2.” C (6,2)= 6!/(2! * (6-2)!) = 6!/(2! * 4!) = 15 Possible Prize Combinations.
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